2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Thermodynamical Processes

JEE Main & Advanced Physics Thermodynamical Processes Question Bank First Law of Thermodynamics

  • question_answer
    When the amount of work done is 333 cal and change in internal energy is 167 cal, then the heat supplied is [AFMC 1998]

    A)            166 cal                                    

    B)            333 cal

    C)            500 cal                                    

    D)            400 cal

    Correct Answer: C

    Solution :

               \[\Delta Q=\Delta U+\Delta W=167+333=500\ cal\]


You need to login to perform this action.
You will be redirected in 3 sec spinner