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JEE Main & Advanced Physics Thermodynamical Processes Question Bank First Law of Thermodynamics

  • question_answer
    In thermodynamic process, 200 Joules of heat is given to a gas and 100 Joules of work is also done on it. The change in internal energy of the gas is                           [AMU (Engg.) 1999]

    A)            100 J                                        

    B)            300 J

    C)            419 J                                        

    D)            24 J

    Correct Answer: B

    Solution :

                       \[\Delta Q=\Delta U+\Delta W\]; \[\Delta Q=200J\] and \[\Delta W=-100J\]            Þ \[\Delta U=\Delta Q-\Delta W=200-(-100)=300J\]


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