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JEE Main & Advanced Physics Thermodynamical Processes Question Bank First Law of Thermodynamics

  • question_answer
    If 150 J of heat is added to a system and the work done by the system is 110 J, then change in internal energy will be [AMU (Engg.) 1999; BHU 2000]

    A)            260 J                                        

    B)            150 J

    C)            110 J                                        

    D)            40 J

    Correct Answer: D

    Solution :

               \[\Delta Q=\Delta U+\Delta W\]\[\Rightarrow \Delta U=\Delta Q-\Delta W=150-110=40\ J\]


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