2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Thermodynamical Processes

JEE Main & Advanced Physics Thermodynamical Processes Question Bank First Law of Thermodynamics

  • question_answer
    In a thermodynamic process, pressure of a fixed mass of a gas is changed in such a manner that the gas molecules gives out 20 J of heat and 10 J of work is done on the gas. If the initial internal energy of the gas was 40 J, then the final internal energy will be                                                [DPMT 2004]

    A)            30 J

    B)            20 J

    C)            60 J

    D)            40 J

    Correct Answer: C

    Solution :

                       \[\Delta Q=\Delta U+\Delta W=({{U}_{f}}-{{U}_{i}})+\Delta W\]            Þ \[30=({{U}_{f}}-40)+10\]Þ \[{{U}_{f}}=60J\]


You need to login to perform this action.
You will be redirected in 3 sec spinner