A) \[{{10}^{5}}\,\]cal
B) \[{{10}^{4}}\]cal
C) \[{{10}^{3}}\] cal
D) \[5\times {{10}^{3}}\]cal
Correct Answer: B
Solution :
From FLOT DQ = DU + DW Work done at constant pressure \[{{(\Delta W)}_{P}}={{(\Delta Q)}_{P}}-\Delta U\] \[{{(\Delta Q)}_{P}}-{{(\Delta Q)}_{V}}\] (As we know \[{{(\Delta Q)}_{V}}=\Delta U\]) Also \[{{(\Delta Q)}_{P}}=m{{c}_{P}}\Delta T\] and \[{{(\Delta Q)}_{V}}=m{{c}_{V}}\Delta T\] Þ \[{{(\Delta W)}_{P}}=m({{c}_{P}}-{{c}_{V}})\Delta T\] Þ \[{{(\Delta W)}_{P}}=1\times (3.4\times {{10}^{3}}-2.4\times {{10}^{3}})\times 10={{10}^{4}}cal\]You need to login to perform this action.
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