JEE Main & Advanced Physics Thermodynamical Processes Question Bank First Law of Thermodynamics

  • question_answer
    One mole of an ideal monoatomic gas is heated at a constant pressure of one atmosphere from \[{{0}^{o}}C\] to \[{{100}^{o}}C\]. Then the change in the internal energy is           [Pb. PMT 2001]

    A)            6.56 joules                             

    B)            \[8.32\times {{10}^{2}}\]joules

    C)            \[12.48\times {{10}^{2}}\]joules                                      

    D)            20.80 joules

    Correct Answer: C

    Solution :

                       Change in internal energy is always equal to the heat supplied at constant volume. i.e. \[\Delta U={{(\Delta Q)}_{V}}=\mu {{C}_{V}}\Delta T.\] For monoatomic gas \[{{C}_{V}}=\frac{3}{2}R\] Þ \[\Delta U=\mu \,\left( \frac{3}{2}R \right)\Delta T=1\times \frac{3}{2}\times 8.31\times (100-0)\] \[=12.48\times {{10}^{2}}J\]


You need to login to perform this action.
You will be redirected in 3 sec spinner