2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Thermodynamical Processes

JEE Main & Advanced Physics Thermodynamical Processes Question Bank First Law of Thermodynamics

  • question_answer
    If \[{{C}_{V}}=4.96cal/mole\] K, then increase in internal energy when temperature of 2 moles of this gas is increased from  340 K to 342 K                                                       [RPET 1997]

    A)             27.80 cal                                

    B)            19.84 cal

    C)            13.90 cal                                 

    D)            9.92 cal

    Correct Answer: B

    Solution :

               \[\Delta U=\mu {{C}_{V}}\Delta T=2\times 4.96\times (342-340)=19.84\ cal\]


You need to login to perform this action.
You will be redirected in 3 sec spinner