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JEE Main & Advanced Physics Thermodynamical Processes Question Bank First Law of Thermodynamics

  • question_answer
    When heat energy of 1500 Joules, is supplied to a gas at constant pressure \[2.1\times {{10}^{5}}N/{{m}^{2}}\], there was an increase in its volume equal to \[2.5\times {{10}^{-3}}{{m}^{3}}\]. The increase in internal energy of the gas in Joules is [EAMCET (Engg.) 1999]

    A)            450                                           

    B)            525

    C)            975

    D)            2025

    Correct Answer: C

    Solution :

                       According to FLOT                    \[\Delta Q=\Delta U+P(\Delta V)\]Þ \[\Delta U=\Delta Q-P(\Delta V)\]            \[=1500-(2.1\times {{10}^{5}})(2.5\times {{10}^{-3}})\]=975 Joule


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