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JEE Main & Advanced Physics Thermodynamical Processes Question Bank First Law of Thermodynamics

  • question_answer
    If heat given to a system is 6 kcal and work done is 6 kJ. Then change in internal energy is             [BHU Med. 2000]

    A)            19.1 kJ                                     

    B)            12.5 kJ

    C)            25 kJ                                        

    D)            Zero

    Correct Answer: A

    Solution :

                       \[\Delta Q=\Delta U+\Delta W\]Þ \[\Delta U=\Delta Q-\Delta W\]            \[=6\times 4.18-6=19.08kJ\]\[\approx 19.1\,kJ\]


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