A) Zero, Zero
B) Zero, \[P{{V}_{1}}\]
C) \[P{{V}_{1}}\], Zero
D) \[P{{V}_{1}},\ {{P}_{1}}{{V}_{1}}\]
Correct Answer: B
Solution :
(i) Case \[\to \]Volume = constant \[\Rightarrow \int_{{}}^{{}}{PdV}=0\] (ii) Case\[\to \]P = constant \[\Rightarrow \int_{\,{{V}_{1}}}^{\,2{{V}_{1}}}{PdV}=P\int_{\,{{V}_{1}}}^{\,2{{V}_{1}}}{dV=P{{V}_{1}}}\]
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