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JEE Main & Advanced Physics Thermodynamical Processes Question Bank First Law of Thermodynamics

  • question_answer
    A system is given 300 calories of heat and it does 600 joules of work.  How much does the internal energy of the system change in this process (J = 4.18 joules/cal)                                                            [MP PET 1991]

    A)            654 Joule                                

    B)            156.5 Joule

    C)            ­­? 300 Joule                            

    D)            ? 528.2 Joule

    Correct Answer: A

    Solution :

                       \[J\Delta Q=\Delta U+\Delta W,\ \ \Delta U=J\Delta Q-\Delta W\]            \[\Delta U=4.18\times 300-600=654\ Joule\]


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