A) t
B) 4t
C) 2 t
D) t/4
Correct Answer: C
Solution :
Time required to emptied the tank \[t=\frac{A}{{{A}_{0}}}\sqrt{\frac{2H}{g}}\] \ \[\frac{{{t}_{2}}}{{{t}_{1}}}=\sqrt{\frac{{{H}_{2}}}{{{H}_{1}}}}=\sqrt{\frac{4h}{h}}=2\] \[\therefore \ \ {{t}_{2}}=2t\]
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