A) \[\frac{V}{16}\]
B) \[\frac{V}{17}\]
C) \[\frac{16V}{17}\]
D) \[\frac{17V}{16}\]
Correct Answer: B
Solution :
Rate of flow of liquid \[V=\frac{P}{R}\] where liquid resistance \[R=\frac{8\eta l}{\pi {{r}^{4}}}\] For another tube liquid resistance \[R'=\frac{8\eta l}{\pi {{\left( \frac{r}{2} \right)}^{4}}}=\frac{8\eta l}{\pi {{r}^{4}}}.16=16R\] For the series combination \[{{V}_{New}}=\frac{P}{R+R'}=\frac{P}{R+16R}=\frac{P}{17R}\] \[=\frac{V}{17}\].
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