A) P
B) \[\frac{3P}{4}\]
C) \[\frac{P}{2}\]
D) \[\frac{P}{4}\]
Correct Answer: D
Solution :
From \[V=\frac{P\pi {{r}^{4}}}{8\eta l}\] Þ \[P=\frac{V8\eta l}{\pi {{r}^{4}}}\] Þ\[\frac{{{P}_{2}}}{{{P}_{1}}}=\frac{{{V}_{2}}}{{{V}_{1}}}\times \frac{{{l}_{2}}}{{{l}_{1}}}\times {{\left( \frac{{{r}_{1}}}{{{r}_{2}}} \right)}^{4}}\]\[=2\times 2\times {{\left( \frac{1}{2} \right)}^{4}}=\frac{1}{4}\] Þ \[{{P}_{2}}=\frac{{{P}_{1}}}{4}=\frac{P}{4}\].
You need to login to perform this action.
You will be redirected in
3 sec
