A) 4 cm3/sec
B) (16/3) cm3/sec
C) (8/17) cm3/sec
D) None of these
Correct Answer: B
Solution :
\[V=\frac{\pi {{\Pr }^{4}}}{8\eta l}=\frac{8c{{m}^{3}}}{\sec }\] For composite tube \[{{V}_{1}}=\frac{P\pi {{r}^{4}}}{8\eta \left( l+\frac{l}{2} \right)}=\frac{2}{3}\frac{\pi P{{r}^{4}}}{8\eta l}\]\[=\frac{2}{3}\times 8=\frac{16}{3}\frac{c{{m}^{3}}}{\sec }\] \[\left[ \because \ \ {{l}_{1}}=l=2{{l}_{2}}\ \text{or}\ {{l}_{2}}=\frac{l}{2} \right]\]
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