question_answer

A liquid flows in a tube from left to right as shown in figure. \[{{A}_{1}}\] and \[{{A}_{2}}\] are the cross-sections of the portions of the tube as shown. Then the ratio of speeds \[{{v}_{1}}/{{v}_{2}}\] will be

A)             \[{{A}_{1}}/{{A}_{2}}\]

B)             \[{{A}_{2}}/{{A}_{1}}\]

C)             \[\sqrt{{{A}_{2}}}/\sqrt{{{A}_{1}}}\]

D)             \[\sqrt{{{A}_{1}}}/\sqrt{{{A}_{2}}}\]