A) 282.8 cm/sec
B) 432.6 cm/sec
C) 632.6 cm/sec
D) 832.6 cm/sec
Correct Answer: A
Solution :
\[\frac{{{v}^{2}}}{2g}=h\]Þ \[v=\sqrt{2gh}\] \[=\sqrt{2\times {{10}^{3}}\times 40}\]=\[2\sqrt{2}\times {{10}^{2}}\]=\[282.8\ cm/s\]
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