A) 9 minute
B) 7 minute
C) 5 minute
D) 3 minute
Correct Answer: B
Solution :
Time taken to be emptied for h height, \[t=\sqrt{\frac{2h}{g}}\] and for \[\frac{h}{2}\] height, \[t'=\sqrt{\frac{2h/2}{g}}=\sqrt{\frac{h}{g}}\] \ \[\frac{t'}{t}=\frac{1}{\sqrt{2}}\Rightarrow t'=\frac{t}{\sqrt{2}}=\frac{10}{\sqrt{2}}=7\ minute\]
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