A) 2
B) 3
C) 4
D) \[2\sqrt{2}\]
Correct Answer: C
Solution :
\[t=\frac{A}{a}\sqrt{\frac{2}{g}}\left[ \sqrt{{{H}_{1}}}-\sqrt{{{H}_{2}}} \right]\] Now, \[{{T}_{1}}=\frac{A}{a}\sqrt{\frac{2}{g}}\left[ \sqrt{H}-\sqrt{\frac{H}{\eta }} \right]\] and \[{{T}_{2}}=\frac{A}{a}\sqrt{\frac{2}{g}}\left[ \sqrt{\frac{H}{\eta }}-\sqrt{0} \right]\] According to problem \[{{T}_{1}}={{T}_{2}}\] \\[\sqrt{H}-\sqrt{\frac{H}{\eta }}=\sqrt{\frac{H}{\eta }}-0\]Þ \[\sqrt{H}=2\sqrt{\frac{H}{\eta }}\Rightarrow \eta =4\]
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