A) \[{{r}_{1}}+{{r}_{2}}\]
B) \[r_{1}^{2}+r_{2}^{2}\]
C) \[r_{1}^{4}+r_{2}^{4}\]
D) None of these
Correct Answer: D
Solution :
\[V={{V}_{1}}+{{V}_{2}}\] Þ \[\frac{\pi P{{r}^{4}}}{8\eta l}=\frac{\pi Pr_{1}^{4}}{8\eta l}+\frac{\pi Pr_{2}^{4}}{8\eta l}\]Þ \[{{r}^{4}}=r_{1}^{4}+r_{2}^{4}\] \ \[r={{(r_{1}^{4}+r_{2}^{4})}^{1/4}}\]
You need to login to perform this action.
You will be redirected in
3 sec
