A) \[4Q\]
B) Q
C) \[\frac{Q}{4}\]
D) \[\frac{Q}{8}\]
Correct Answer: D
Solution :
\[V=\frac{\pi p{{r}^{4}}}{8\eta l}\] \\[V\propto P\,{{r}^{4}}\] (\[\eta \ \text{and }l\] are constants) \ \[\frac{{{V}_{2}}}{{{V}_{1}}}=\left( \frac{{{P}_{2}}}{{{P}_{1}}} \right)\ {{\left( \frac{{{r}_{2}}}{{{r}_{1}}} \right)}^{4}}\]= \[2\times {{\left( \frac{1}{2} \right)}^{4}}\]= \[\frac{1}{8}\]\ \[{{V}_{2}}=\frac{Q}{8}\]
You need to login to perform this action.
You will be redirected in
3 sec
