A) 7 \[m{{s}^{-1}}\]
B) 8 \[m{{s}^{-1}}\]
C) 9 \[m{{s}^{-1}}\]
D) 10 \[m{{s}^{-1}}\]
Correct Answer: D
Solution :
\[\frac{{{P}_{1}}-{{P}_{2}}}{\rho g}=\frac{{{v}^{2}}}{2g}\] Þ \[\frac{4.5\times {{10}^{5}}-4\times {{10}^{5}}}{{{10}^{3}}\times g}=\frac{{{v}^{2}}}{2g}\]\ v=10m/s
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