A) 3 m/s
B) 6 m/s
C) 12 m/s
D) 8 m/s
Correct Answer: C
Solution :
\[{{a}_{1}}{{v}_{1}}={{a}_{2}}{{v}_{2}}\] Þ \[\frac{{{v}_{2}}}{{{v}_{1}}}=\frac{{{a}_{1}}}{{{a}_{2}}}={{\left( \frac{{{r}_{1}}}{{{r}_{2}}} \right)}^{2}}\] Þ \[{{v}_{2}}=3\times {{(2)}^{2}}\]= 12 m/sYou need to login to perform this action.
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