Railways Technical Ability Fluid Mechanics and Machinery Question Bank Fluid Mechanics

  • question_answer The standard sea level atmospheric pressure is equivalent to:                                   

    A) 10.2 m of freshwater of \[\rho =998\,\,\text{kg/}{{\text{m}}^{\text{3}}}\]

    B) 10.2 m of salt water \[\rho =1025\,\,\text{kg/}{{\text{m}}^{\text{3}}}\]

    C) 25.5 m of kerosene of \[\rho =800\,\,\text{kg/}{{\text{m}}^{\text{3}}}\]

    D) 6.4 m of carbon tetrachloride of \[\rho =1590\,\,\text{kg/}{{\text{m}}^{\text{3}}}\]

    Correct Answer: B

    Solution :

    At sea level, h = 760 mm of Hg A.         \[\frac{760\times {{10}^{-3}}\times 13.6\times 9.81\times {{10}^{3}}}{9.81\times 998}=10.35\,\,m\] B.         \[\frac{760\times {{10}^{-3}}\times 13.6\times {{10}^{3}}}{1025}=10.08\,\,m=10.1\,m\] C.         \[760\times {{10}^{-3}}\times 13.6/0.8=12.92\,m\] D.        \[760\times {{10}^{-3}}\times 13.6/1.590=6.5\,m\]


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