A) 2
B) 4
C) \[2\,\sqrt{2}\]
D) \[4\,\sqrt{2}\]
Correct Answer: C
Solution :
\[\phi ={{x}^{2}}-{{y}^{2}}\] \[u=\frac{\partial \phi }{\partial x}=-\,2x\] \[v=-\frac{\partial \phi }{\partial y}=+\,2y\] \[v=\sqrt{{{u}^{2}}+{{v}^{2}}}=\sqrt{4{{x}^{2}}+4{{y}^{2}}}\] \[{{v}_{\left( 1,1 \right)}}=\sqrt{8}=2\sqrt{2}\]You need to login to perform this action.
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