A) \[23\] sq. units
B) \[\frac{23}{2}sq.\]units
C) \[\frac{23}{3}sq.\]units
D) None of these
Correct Answer: C
Solution :
Here O is the point \[(0,\,0)\]. The line \[2x+3y=12\] meets the y-axis at B and so B is the point (0,4). The equation of any line perpendicular to the line \[2x+3y=12\] and passes through (5, 5) is \[3x-2y=5\] ......(i) The line (i) meets the x-axis at C and so co-ordinates of C are\[\left( \frac{5}{3},\,0 \right).\]Similarly the coordinates of E are (3, 2) by solving the line AB and (i). Thus O(0, 0), \[C\left( \frac{5}{3},0 \right)\], \[E(3,\,2)\] and B (0, 4). Now the area of figure \[OCEB=\] area of \[\Delta OCE\] + area of \[\Delta OEB=\frac{23}{3}sq.\]units.You need to login to perform this action.
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