Answer:
\[t=8s\] \[m=10\,kg\]
After the force stops acting, the body moves with a uniform velocity (v) given by
\[v=\frac{dis\tan ce\,\,travelled}{time\,taken}=\frac{80}{5}m/s\]
Now, Applying v = u + at
\[\Rightarrow 16=0+a\times 8\] \[(\because u=0)\]
\[\Rightarrow a=2m/{{s}^{2}}\]
\[\therefore F=ma=10\times 2=20N\]
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