Answer:
\[m=250\,\,g=0.25\,kg\]
\[u=10m/s\]
\[v=25m/s\]
\[Time=t=4\,\sec \]
\[F=?\]
We know that \[F=ma=n\left( \frac{v-u}{t} \right)\] …..(1)
\[\left( \because a=\frac{v-u}{t} \right)\]
\[\therefore \]Substituting the above values in (1), we have,
\[F=0.25\left( \frac{25-10}{4} \right)=0.25\left( \frac{15}{4} \right)\]
\[\Rightarrow F=\frac{1}{4}\times \frac{15}{4}=\frac{15}{16}N\]
Therefore, force acting on the particle is\[\left( \frac{15}{16} \right)N.\]
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