Answer:
Given m = 0.3 kg, Spring constant
\[K=15N/m\]
elongation \[x=20cm=\frac{20}{100}m,\,\,a=?\]
We know, \[F=-kx\]
\[\Rightarrow ma=-ka\,\,\Rightarrow 0.3\times a=-15\times \frac{1}{5}\]
\[=a=\frac{3}{0.3}=10m/{{s}^{2}}\]
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