Answer:
Given \[a=2m/{{s}^{2}},\,\,\,m=2kg\]
when the elevator moves upwards
\[kx-mg=ma\Rightarrow kx=mg+ma=m(g+a)\]
\[=2(10+2)=100x\therefore x=\frac{24}{100}=0.24m\]
when 1 kg is added, total mass = 3 kg
Now, \[Kx|-mg=ma\Rightarrow Kx|=mg+ma\]
\[=m\times (g+a)=3(10+2)=36\]
\[\Rightarrow x'=\frac{36}{100}=0.36m\]
\[\therefore \]Further elongation \[=0.36-0.24\]
\[=0.12m\]
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