Answer:
No. of bullets, n = 216 Time taken, t = 1 min = 60 s Mass of the bullet, \[m=50\,g\,\,g=\frac{50}{1000}kg\,\,=\frac{1}{20}kg\] Final velocity, \[v=1000\,\,m/s\] Initial velocity,\[u=0\] Force required,\[F=?\] \[F=n\times m\times a=n\times m\times \frac{(v-u)}{t}\] \[\therefore F=\frac{nm(v-u)}{t}\] \[\therefore F=\frac{216\times \frac{1}{20}(1000-0)}{60}=\frac{216\times 1000}{20\times 60}N\] \[=180N\] \[\therefore \] The force required to hold the gun = 180 N
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