Answer:
\[u=0,\,\,v=5\times {{10}^{6}}m/s,\,\,\,s=1cm=\frac{1}{100}m,\,\,F=?,\,\,m=9.1\times {{10}^{-31}}kg\] We know,\[F=ma\] How to get a? Applying, \[a=\frac{{{V}^{2}}-{{u}^{2}}}{2s}=\frac{(5\times {{10}^{6}})-{{0}^{2}}}{2\times {}^{1}/{}_{100}}\] \[=\frac{25\times {{10}^{12}}\times {{10}^{2}}}{2}=12.5\times {{10}^{14}}m/{{s}^{2}}\] \[\therefore F=9.1\times {{10}^{-31}}=12.5\times {{10}^{14}}N\] \[=113.75\times {{10}^{-17}}=1.1\times {{10}^{-15}}N.\]
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