Answer:
\[{{m}_{1}}=25kg,\,\,{{u}_{1}}=40m/s\] \[{{m}_{2}}=15kg,\,\,{{u}_{2}}=0\] \[{{v}_{1}}={{v}_{2}}=v\] From law of conservation of momentum we know that, \[{{m}_{1}}{{u}_{1}}+{{m}_{2}}{{u}_{2}}={{m}_{1}}{{v}_{1}}+{{m}_{2}}{{v}_{2}}\] \[\Rightarrow {{m}_{1}}{{u}_{1}}+{{m}_{2}}{{u}_{2}}={{m}_{1}}v+{{m}_{2}}v({{v}_{1}}={{v}_{2}}=v)\] \[\Rightarrow 25\times 40+15\times 0=(25+15)v\] \[\Rightarrow v=\frac{1000}{40}=25m{{s}^{-1}}\]
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