A) 8 N
B) \[\text{2}\times \text{1}{{0}^{\text{4}}}\text{ N}\]
C) 4 N
D) \[{{10}^{4}}\,N\]
Correct Answer: B
Solution :
Given, \[m=2\text{ }kg\text{ }u=100\text{ }m/s\] \[v=\text{ }100\text{ }m/s\] (\[\because \] the body is rebounding) \[F=?\] we know, \[F=ma=m=\left( \frac{v-u}{t} \right)\] \[\left( \because a=\frac{v-u}{t} \right)\] \[\Rightarrow \] \[2\times \left( \frac{-100-100}{\frac{1}{50}} \right)\] \[=2\times \text{ }200\times 50=\text{ }2\times {{10}^{4}}N\] (\[\because \] the negative sign indicates the force is in opposite direction) \[\therefore \] \[F=2\times {{10}^{4}}N\]
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