A) 0.5s
B) 0.2s
C) 0.4s
D) 0.25s
E) (e) \[\text{125}\times \text{25}0\text{s}\]
Correct Answer: A
Solution :
Given, \[F=250\text{ }N\] Momentum \[(\Delta p)=125\text{ }kg\text{ }m/s\text{ }\Delta t=?\] we know, \[F=\frac{change\text{ }in\text{ }momentum}{change\text{ }in\text{ }time}=\frac{\Delta p}{\Delta t}\] \[\Rightarrow \] \[\Delta t=\frac{\Delta p}{F}=\frac{125}{250}=\frac{1}{2}=0.5\,s\]
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