A) \[\text{2}.\text{5 m}{{\text{s}}^{\text{2}}}\]
B) \[\text{5m}/{{\text{s}}^{\text{2}}}\]
C) \[\text{1}0\text{ m}/{{\text{s}}^{\text{2}}}\]
D) \[\text{5 m}/{{\text{s}}^{\text{2}}}\]
Correct Answer: A
Solution :
Given, Mass of metal\[(m)=2kg\] the velocity at which water struck. \[v=5\text{ }m/s\] The rate at which water struck \[\left( \frac{m}{t} \right)=1\,kg/s\] acceleration\[(a)=?\] we know, \[F=ma=m\left( \frac{v-u}{t} \right)\] \[\left( \because a=\frac{v-u}{t} \right)\] \[\Rightarrow \] \[F=\frac{mv}{t}\] (\[\because \]the metal is resting, \[u=0\]) \[\Rightarrow \] \[1\times 5=5\,N\] From equation F = ma, we get \[a=\frac{N}{m}\] \[\Rightarrow \] \[a=\frac{5}{2}=2.5\,m/{{s}^{2}}\]
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