Answer:
(a) Resultant force on the system = 70 N towards right\[7a=70\Rightarrow \,\,\,a=10m/{{\sec }^{2}}\] (b) Draw the free body diagram 1kg block
Resultant force on 1 kg block \[=(120-N)\] \[\Rightarrow (120-N)=(1)10N\Rightarrow 110\]newton. (c) The net force on 2kg block. \[{{F}_{net}}\] = (mass of 2kg block) × acceleration \[=2\times 10=20N.\]
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