A) \[\frac{g+a}{3}\]
B) \[\frac{g-a}{3}\]
C) \[\frac{4m(g+a)}{3}\]
D) \[\frac{m(g-a)}{3}\]
Correct Answer: C
Solution :
Let mass \[2m\] come downwards with acceleration \[x\] relative to pulley.You need to login to perform this action.
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