A) \[100\,\,N\]
B) \[200\,\,N\]
C) \[300\,\,N\]
D) \[400\,\,N\]
Correct Answer: B
Solution :
\[m=0.1\,\,kg\], \[V=10\,\,m\,\,{{s}^{-1}}\] Before coming into contact with the bat, its momentum\[({{m}_{1}})=0.1\times 10=1\,\,kg\,\,m\,\,{{s}^{-1}}\]. After coming into contact with the bat, the direction of its velocity gets reversed, i.e. its velocity will be \[=-10\,\,m\,\,{{s}^{-1}}\]. \[\therefore \]Now, its momentum is\[({{m}_{2}})\] \[=0.1\times -10=-1\,\,kg\,\,m\,\,{{s}^{-1}}\] \[\text{F=}\frac{\text{Change}\,\,\text{of}\,\,\text{momentum}}{\text{Time}}=\frac{{{m}_{2}}-{{m}_{1}}}{t}\] \[\therefore \]\[F=\frac{(-1)-1}{0.01}=\frac{-2}{0.01}=-200\,\,N\]
You need to login to perform this action.
You will be redirected in
3 sec
