A) 49 cm/sec
B) 147 cm/sec
C) 98 cm/sec
D) 196 cm/sec
Correct Answer: C
Solution :
Weight of the dish\[=\frac{10}{1000}\times g\] Speed of the bullet \[=v\] Rate of change of momentum of bullets \[=\frac{2\times 10\times 5}{1000}v\]\[=\]applied force on the dish Now,\[\frac{2\times 10\times 5}{1000}v=\frac{10\times g}{1000}\] \[\therefore \] \[v=0.98\,\,m/s=98\,\,cm/s\]You need to login to perform this action.
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