A) \[100\,\,N\]
B) \[-10\,\,N\]
C) \[-40\,\,N\]
D) \[1N\]
Correct Answer: C
Solution :
\[m=0.1\,\,kg,\,\,V=20\,\,m\,\,{{s}^{-1}}\] Before coming into contact with the bat, its momentum\[({{m}_{1}})=0.1\times 20=2\,\,kg\,\,m\,\,{{s}^{-1}}\] After coming into contact with the bat, the direction of its velocity gets reversed, i.e. its velocity will be \[=-20\,\,m\,\,{{s}^{-1}}\],\[\therefore \]Now, its momentum\[({{m}_{2}})\] \[=0.1\times -20=-2\,\,kg\,\,m\,\,{{s}^{-1}}\] \[\text{F=}\frac{\text{Change}\,\,\text{in}\,\,\text{momentum}}{\text{Time}}\] \[=\]Rate of change of momentum. \[=\frac{{{m}_{2}}-{{m}_{1}}}{t}\],\[\therefore F=\frac{(-2)-2}{0.1}=\frac{-4}{0.1}=-40\,\,N\]
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