9th Class Science Force and laws of motion Question Bank Force and Laws of Motion

  • question_answer
    A force acts for \[10s\] on a body of mass \[10\,\,kg\] after which the force ceases and the body travels \[50\,\,m\] in the next\[5\,\,s\]. Find the magnitude of the force.

    A) \[5\,\,N\]                       

    B)        \[10\,\,N\]  

    C) \[15\,\,N\]         

    D)        \[50\,\,N\]

    Correct Answer: B

    Solution :

    \[u=0;\,\,m=10\,\,kg;\,\,t=10\,\,s\] After the force ceases, the body covers \[50\,\,m\] in\[5\,\,s\]. Therefore, the final velocity of the body, \[\text{v=}\frac{\text{Distance}}{\text{Time}}\text{=}\frac{\text{50}}{\text{5}}\text{=10}\,\,\text{m}{{\text{s}}^{\text{-1}}}\] Now, \[v=u+at\] \[\therefore \]\[10=0+a\times 10\]or\[a=1\,\,m\,\,{{s}^{-2}}\] Therefore, force applied on the body, \[F=ma=10\times 1=10\,\,N\]


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