A) \[-25\]
B) \[-50\]
C) \[-75\]
D) \[-100\]
Correct Answer: B
Solution :
\[W=mg=10\,\,m\,\,N\] When lift is moving downwards, the apparent weight is given as: \[W=m(g-a)=m(10-5)=5\,\,m\,\,N\]\[%\]Change in weight\[=\frac{{{w}_{1}}-w}{w}\times 100=\frac{5\,\,m-10\,\,m}{10\,\,m}\times 100\] \[=-\frac{1}{2}\times 100=-50%\]You need to login to perform this action.
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