Answer:
\[{{P}_{1}}{{V}_{1}}={{P}_{2}}{{V}_{2}}\] \[\Rightarrow \]\[9.962\times {{10}^{4}}\times 95=10.13\times {{10}^{4}}\times {{V}_{2}}\] \[\Rightarrow \] \[{{V}_{2}}=\frac{9.962\times {{10}^{4}}\times 95}{10.13\times {{10}^{4}}}=93.424\text{ }c{{m}^{3}}\]
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