Answer:
\[{{P}_{1}}{{V}_{1}}={{P}_{2}}{{V}_{2}},700\times 250={{P}_{2}}\times \left( \frac{4}{5}\times 250 \right),\] \[{{P}_{2}}=875mm\] Additional pressure \[=875700=175\text{ }mm\] of\[Hg\].
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