Answer:
Mass of book \[(m)=20\text{ }g=\frac{20}{1000}kg=\frac{1}{50}kg\] Thrust (T) = ? Acceleration due to gravity \[(g)=10\text{ }m{{s}^{2}}\] We know, Thrust \[(T)=mg\] \[T=\frac{1}{50}\times 10=\frac{1}{5}N=0.2\,N\] Therefore, the thrust acting on the table by the book is 0.2 N.
Therefore, the thrust acting on the table by the book is 0.2 N.
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