question_answer

Express a pressure of \[2\text{ }\times \text{ }{{10}^{5}}\]pascal in units of  (i) bar (ii) dyne \[c{{m}^{-2}}\]and (iii) millibar

Answer:

(i) Pressure\[=2\times {{10}^{5}}\]pascal = 2 bar                                  (\[\because \]1 bar\[={{10}^{5}}\]Pa) (ii) Pressure \[=2\times {{10}^{5}}\] pascal \[=2\times {{10}^{5}}\times 10\text{ }dynes\text{ }c{{m}^{2}}\]                                 (\[\because \]1 pascal = 10 dyne\[c{{m}^{2}}\]) (iii) Pressure\[=2\times {{10}^{5}}\]pascal \[=2\times {{10}^{5}}\times {{10}^{2}}\]pascal \[=2\times {{10}^{3}}\]millibar            (\[\because \]1 millibar\[={{10}^{2}}\] Pa)