Answer:
\[P=25,000\text{ }Pa\] \[A=0.50\text{ }c{{m}^{2}}=0.000050\text{ }{{m}^{2}}\] \[F=?\] \[P=\frac{F}{A}\] \[\Rightarrow \] \[F=P\times A\] \[\therefore \] \[F=25,000\times 0.\text{ }000050=1.25\text{ }N\]
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