A) \[5\times {{10}^{-5}}\,N/m\]
B) \[5\times {{10}^{-3}}\,N/m\]
C) \[2.5\times {{10}^{-5}}\,N/m\]
D) \[2.5\times {{10}^{-4}}\,N/m\]
Correct Answer: A
Solution :
\[F=\frac{{{\mu }_{0}}}{4\pi }\frac{2\times {{i}_{1}}{{i}_{2}}}{a}=\frac{{{10}^{-7}}\times 2\times 5\times 5}{0.1}=5\times {{10}^{-5}}N/m\]
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