A) 0.15 \[ampere-{{m}^{2}}\]
B) 0.3 \[ampere-{{m}^{2}}\]
C) 0.45 \[ampere-{{m}^{2}}\]
D) 0.6 \[ampere-{{m}^{2}}\]
Correct Answer: B
Solution :
\[M=NiA=20\times \frac{22}{7}{{(4\times {{10}^{-2}})}^{2}}3=0.3\,A-{{m}^{2}}\]
You need to login to perform this action.
You will be redirected in
3 sec
